Question

G Ask Your Teacher My Netes Total plasma volume is important in determining the required plasme component in blood replacement theraoy for a person undergoing surgery. Masma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 43 male firefightars are tested and that they have a plasma volume semple mean of x 37.5 m/kg (mililiters plasme per kilogram body weight). Assume that o-7.30 ml/kg for the diatributian of blood plasma Pra (a) Find a 99%6 confidence interval for the population mean blood plasma volume in male firefighters What is the margin of errer? (Round your anawers to twe dedimal places.) lower limit upper Smit margin of error () What conditions are necessary for your calculations? (Select all that apply.) the distribution of weights is nermal is known heck the distribution of weights is uniform n is large eis unknown (c) Interpret your resuts in Uhe context of this problem e 1 % of the intervals created using this method will contain the true average blood plasma volume in male frefighters o 99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters The probabilty that this interval contains the true average blood plasma velume in male firefighters is 0.01 o The probabilty that this interval contains the true average blood plasma volume in male firefighters is 0.99 id res iu ma (d) Find the semple size necessary for a 99% conidence level with maximal margin of eror E-2.50 for the mean plasma velume in male firefighters. (Round up to the nearest whole number) male frefighters

Answer 1

sol Q=0.01 r = 37.5 T = 7.30 n=43 (a) 99 •%• confidence internal 5 + Zelez* Ší sem 7.30 20.012= 20.005 = 2.576 CI. = 37.5 † 2-576* This = 37.5 + 2.06770 Lower limit = 37.5 -2.06770 = 34.63 upper limit = 37.5 + 2.86710 = 40.37 yor = 9.576 *. * 7:36 287 43 weights is normal . (b) (i) The distribution of . ü o is known - id) n is large - (C) option (b) is right - 99.1. of CI created using this method would include - the true catch and release mortality rate. Scanned with CamScanner

ca) E = 2.50 2 n = (2.5340) n . n . 1 2.576*7.30 \ (-2.50 ) 2.50 n= 56.755 na 57 male fighters are Due to HomeworkLib Polity, I have to attend only finest question. Thank you. cs Scanned with CamScanner