A certin gas expans in volume from 2.0 L to 0.6 L at a constant tempature. Caculate the work done under the following conditions:
a. expansion agasint external pressure of 1.2 atm
b. expansion aganist a vacuum
a)
external pressure = 1.2 atm
work done = - pdv
= - 1.2 x (6 - 2)
= - 4.8 L.atm
work done = - 4.8 x 101.325 = - 486.5 J
work done = - 486.5 J
b)
in vaccum , the external pressure = 0
work done = 0 J
Note : expands from 2.0 to 6.0 L not 0.6 L
A certin gas expans in volume from 2.0 L to 0.6 L at a constant tempature....
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