Question

Given an array and a starting position write a function replaceFromN, that takes an integer array 'array', the size of the array size and a starting positions 'n' as parameters and replaces the elements starting from that index onward with the sequence 1,2,3,... The function returns nothing.

void replaceFromN(int array[], int size, int n)

For example, given

array= {15,12,4,9,2,3}

n =2

the function should modify array to be {15,12,1,2,3,4}

Answer 1

#include <iostream>

using namespace std;

// Function declaration
void replaceFromN(int array[], int size, int n);
int main()
{
// Declaring an array
int array[] = { 15, 12, 4, 9, 2, 3 };

// Displaying the elements of an array
cout << "Displaying the elements in the array before replacing :" << endl;
for (int i = 0; i < 6; i++)
{
cout << array[i] << " ";
}

/* calling the function by passing
* array,size,index val as arguments
*/
replaceFromN(array, 6, 2);
return 0;
}

/* This function will replace the
* elements of an aray from the index n
* with sequence of values
*/
void replaceFromN(int array[], int size, int n)
{
int seq = 0;
for (int i = 0; i < size; i++)
{
if (i >= n)
{
array[i] = ++seq;
}
}

// Displaying the elements of array
cout << "\nDisplaying the elements in the array after replacing :" << endl;
for (int i = 0; i < size; i++)
{
cout << array[i] << " ";
}
}

__________________

Output:

CAProgram Files (x86)\Dev-CpplMinGW64\bin ReplacingElementsOfArrayWithSequence.exe Displaying the elements in the array before replacing 15 12 4 9 2 3 Displaying the elements in the array after replacing: 15 12 1 2 3 4 Process exited after 0.05518 seconds with return value 0 Press any key to continue . - .

_________Thank YOu