4) A large number of voltages show a mean of 118.5V and a population standard deviation...

Question

Question

math Statistics-And-Probability

Answer 1

Answer #1

Given, $\mu$ = 118.5, $\sigma$ = 1.20

P( X < x) = p( Z < x - $\mu$ / $\sigma$ )

We have to find P( 116 < X < 120) = ?

P( 116 < X < 120) = P( X < 120) - P( X < 116)

= P( Z < 120 - 118.5 / 1.2) - P( Z < 116 - 118.5 / 1.2)

= P( Z < 1.25) - P( Z < -2.0833)

= 0.8944 - ( 1 - 0.9814)

= 0.8757

= 87.57%

Percentage of data falls between 116 and 120 = 87.57%

Answer 2

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