Homework Answers
let us consider p is the probability of student to success each course = 0.9
n is the total course taken = 4
since this is the case of binomial distribution so
P (x 
= P( x=3 )
+ P(x =4)
= 4C3 (0.9)3(0.1)1 + 4C4 (0.9)4(0.1)0
= 0.2916 + 0.6561
= 0.9477
prob of success at least from 3 courses is 0.9477
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