7.
a.
Given data,
sample proportion is between 0.3 and 0.7 = 0.5
confidence level is 90%
margin of error 2.5%
Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.1 is = 1.645
Sample Proportion = 0.5
ME = 0.025
n = ( 1.645 / 0.025 )^2 * 0.5*0.5
= 1082.41 ~ 1083
b.
given data,
margin of error = 2.5%
confidence level is 90%
standard deviation is 20
Compute Sample Size
n = (Z a/2 * S.D / ME ) ^2
Zα/2 at 0.1% LOS is = 1.645 ( From Standard Normal Table )
Standard Deviation ( S.D) = 20
ME =0.025
n = ( 1.645*20/0.025) ^2
= (32.9/0.025 ) ^2
= 1731856 ~ 1731857
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14. Select the number of participants in the Beck & Watson
study
Group of answer choices
8
13
22
35
15. Beck & Watson determined their final sample size via
Group of answer choices
coding
saturation
triangulation
ethnography
16.Through their study, Beck & Watson determined
Group of answer choices
after a traumatic birth, subsequent births have no troubling
effects
after a traumatic birth, subsequent births brought fear, terror,
anxiety, and dread
Subsequent Childbirth After a Previous Traumatic Birth Beck, Cheryl...
10. The Beck & Watson article is a
Group of answer choices
quantitative study
qualitative study
11. Beck & Watson examined participants' experiences and
perceptions using what type of research design?
Group of answer choices
particpant obersvation
phenomenology
12. Select the participants in the Beck & Watson study
Group of answer choices
Caucasian women with 2-4 children
Caucasian pregnant women
13. In the Beck & Watson study, data was collected via
a(n)
Group of answer choices
internet study
focus group...