Question

7). (15 points) An electron moving perpendicular to a uniform magnetic field of 3.2 x 102 T moves in a circle of radius 0.40 cm. What is the period of circular motion of the electron? (m el 9.11 x 1031 kg, e 1.60 x 1019 C)

Answer 1

WE know that radius of a charge particle in a magnetic field is

$r=\frac{mv}{qb}$

$0.4*10^{-2}=\frac{9.11*10^{-31}v}{1.6*10^{-19}*3.2*10^{-2}}$

v=22480790.34 m/s

now, the time peroid is,

$T=\frac{2 \pi r}{v}$

$T=\frac{2 *3.14*0.4*10^{-2}}{22480790.34}$

T=1.1174*10^-9 seconds