Two masses are connected by a string over an ideal pulley as
shown. The coefficient of kinetic friction between m1 and the table
surface is
. Find an expression
for their common speed after the blocks have moved a distance L.
You can assume that you know: m1, m2, L, and
. (i.e. It's ok for
those variables and any known constants to appear in your answer.)
Show all work. Diagram here:
http://imgur.com/CUMJmPZ
the driving force is m2 g
less the friction force which is m1 g ??
These are constant so there is constant acceleration. You are
permitted L but not t.
So you need to use energy. 1/2 (m1 + m2) v^2 = F * L = g(m2 - m1??
)
Two masses are connected by a string over an ideal pulley as shown. The coefficient of...
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The two masses "m1" and "m2" shown in the figure connected by a
massless string and are being dropped by a constant horizontal
force F a rough horizontal surface. F = 100 N, m1=10 kg, m2=15 kg
coefficient kinetic friction between each mass and M_k= 0.2
expression: M2-->M1--> F
Questions:
1) Calculate the friction force on M2
2) Calculate the acceleration of the system of the 2 masses
3) Calculate the tension T in the string.
H Mz mi
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