5. Its an example for Acidic Buffer
pH = pKa + log (concentration x volume)salt/ (concentration x volume)Acid
= 3.86 + log [(1x 25)/ 1x 75)]
= 3.86 + log (1/3)
= 3.86 -0.48
pH = 3.38
6. Its an example for Acidic Buffer
The added OH- will reacts with acid and forms salt . Hence salt concentration will increases and acid concentration decreases.
Hence, pH = pKa + log {[salt] + 0.01 / [Acid] - 0.01}
pH = 4.76 + log {0.5 + 0.01/ 0.5 - 0.01}
pH = 4.76 + log (0.51/0.49)
pH = 4.76 + log (1.04)
= 4.76 + 0.017
pH = 4.77
Calculate the pH of a buffer solution prepared by mixing 75 mL of 1.0 M lactic...
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