Question

2. A ball (m = 5 kg) travels to the right with a intial velocity of 10 m/s and hits a stationary ball (M = 15 kg). They undergo a perfectly elastic collision. (a) What is the velocity after the collision of ball 17 (12 points) (b) What is the velocity after the collision of ball 2? (11 points)

Answer 1

Vielos bale 2 af ti yomon tot 2 27th Nat - myze? Since. Two balls collides elastically so their momentum and Kinetic energy conserved. let ? t be the final velocity of the ball 1 and Vii, uzi inetrial veloclty, So mvit mvzi= myatt mvi? Įmyzi? Ź munt than it - 2 franci, Vzizo, cause it was stationares, muli mv. 05810=5Uqt & 15Vqf an - Vi f +3124 = 10 know (2) Delta 5x (10)2 = 5.vie + 15 28? is to it? + 3 V28² = 100 -(4) Vit = 1o-3 Vzt putratue of Vit eru (10 -3N27 J² +3v2 = 100 10o -60V 2ft 9 V 28 +32 2 = 100. - Gover +12v22²=0 "V,;? 2 2 from (3) N22 = 510. wie es wie By Ther, if = 10-305=-5uf V24 =5, if V 22=0 vif = 10 - 30o = to So So V2f = 510, then if = -5/610, since mass of Vet is much greater than omass of it, so after collision, Uzf cannot be o; so do 22 stands for 5, (as the velocity of ball I is-5m/s atiter collision. Vif stand for-5. (6) the veloclty of ball2 in 5 mis after collision.