Calculate the order of magnitude ?( ) of the following functions, assuming that T (1) = ? (1).
T(n) = 5T(n/7) + nlogn
T(n) = 3T(n/4) + log3n
T(n) = 4T(n/4) + nlogn
T(n) = 9T(n/10) + log3n
T(n) = 2T(n/3) + n/log2n
T(n) = T(n-1) + 1/n
Answer:
1. T(n) = 5T(n/7) + nlogn
Using Master's theorm , we have :
a = 5 , b = 7 , c = 1 , k = n
log a base b = log 5 base 7 = 0.827
log a base b < c
Therefore T(n) = theta(n^c) = theta(n^0.827) = theta(n)
2. T(n) = 3T(n/4) + log3n
Using Master's theorm , we have :
a = 3 , b = 4 , c = 0 , k = 3
log a base b = log 3 base 4 = 0.792
log a base b > c
therefore T(n) = theta(f(n)) = theta(log3n)
3. T(n) = 4T(n/4) + nlogn
Here a = 4 , b = 4 , c = 1 , k = 1
log4 base 4 = 1 , here log a base b = c
Therefore , T(n) = theta(n^clog^k+1n) = theta(n^1log^k+1n) = theta(nlog^2n
4. T(n) = 9T(n/10) + log3n
Here a = 9 , b = 10 , c = 0 , k = 3
log 9 base 10 = 1 , c = 0
here loga base b > c , therefore T(n) = theta(f(n) = theta(log3n)
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