
3. (10 points) Find the equation of the tangent line to the curve x² + xy...
at the point (2,1)
Find an equation for the tangent line to the curve 22 - xy - y2 - 1 at the point
(1 point) Use implicit differentiation to find an equation of
the tangent line to the curve 2xy3+xy=302xy3+xy=30 at the point
(10,1)(10,1).
(1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3 + xy = 30 at the point (10, 1). The equation -3/70 defines the tangent line to the curve at the point (10, 1).
-/10 POINTS Find an equation of the tangent line for the curve x=tet, y=t+et at the point corresponding to t=0.
Find an equation for the line tangent to the graph of y=x3+ √xy + y3=3 at the point (1,1).
5. Given the function x²y = 8 – xy Find the equation of the tangent line to the curve at the point (-2,1)
Consider the curve defined by the equation x² + xy + y2=4. The equation of the tangent line to the curve at the point (-2,2) is (show work)
Find the equation of the tangent line to the curve at the given
point using implicit differentiation. Remember: equation of a line
can be found by y-y1=m(x-x1) where m is the slope of the line and
(x1,y1) is any point on the line.
Curve:
at (1,1)
Consider the curve to x? + xy + y2 = 4. defined by the equation The equation of the tangent line at the point (-2,2) is the curve
16. [10pts.) Find an equation of the tangent line to the curve y = 4x2 at the given point (1,1). Find the slope using the definition of the derivative: f'(x)= lim f(x+h)-f(x) h
4. Find the equation of the tangent line to curve 3 (x2 + y2) ? = 25 (x2 - y2),= 1 at (2,1).