Question

+ PSS: Simple Harmonic Motion II: Energy ① 2 0f7 Constants Learning Goal: Part B To practice Problem Solving Strategy: Simple Harmonic Motion Il: Energy A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s. What is the kinetic energy K of the toy when the spring is compressed 3.3 cm from its equilibrium position? What is the kinetic energy of the object on the spring when the spring is compressed 3.3 cm from its equilibrium position? Express your answer in joules using three significant figures. AD O 2 ? Submit Request Answer EVALUATE your answer Part What is the potential energy U of the toy when the spring is compressed 3.3 cm from its equilibrium position? Express your answer in joules using three significant figures. Y AL O 2 ? Submit Request Answer

Answer 1

2=0 Pant B mcas , ne se 3* soxio" Amplice of oscillation A=6cm = 0.06m maymum velocity, Vmax = 3.2 mlo frem the commenvakion of energy theorem total mechanical energy a total mechanical energy at the af equilibrium hight exptenced point of the spring § 2 + 2 mula 2 ke ² + 2 m 2 , when ka apring 2 constant kle know et equilibrium point ano, and has the maximum velocity And at the position of a=A, Vg = 0, so the above equation becomes Kemvoray = KA2 on the spring contant mv *= m Vam (50 Mo 2g)(3.2013) 42 (0.06m) 2 ng cong ty k=142.22 3)2

How the kinetic energy of the object on the spring when 9=3.3 cm & found as below mama + 2 kr = (KE) + 2 kre? We know, neq=0 so, kinetic energy at s= 3.3 cm = 3.34102m a 11 + le 20- let al of (10 26 2 C ) of & Van der = RE + & ka? kinetic energy K = 4 m va, 4 kỷ - ( x ) ( a - (14-04) 3x - (K= 1. 77X10l J Part-c Potential energy at n= 3.3 em as x= 3.3 cm = 3.3610-2 m Usa ka? d (142. PPM) (3.3 810*?m) = 7.74810383
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Part b) the kinetic energy was found to be K=1.77*10^-1 J.

Part c) the potential energy was found to be U=7.74*10^-2 J.