Question

Stuck on how to calculate PPM. Can someone please explain this to me!

Determine the concentrations of K2SO4, K+, and SO42- in a solution prepared by dissolving 2.36 x 10-4 g K2SO4 in 1.50 L of water. Express all three concentrations in molarity. Additionally, express the concentrations of the ionic species in parts per million (ppm). Note: Determine the formal concentration of SO42-. Ignore any reactions with water. [K, SO4) = 9.03 x10-7 M [K+] = 1.806 x10-6 M [K+] = 4.04 *10-4 ppm [SO2-) = 9.03 <10-7 M [SO2-) = 4.97 X10 -4 ppm

Answer 1

Given, [k +] = 1.806 X10-6 M and [sol] 9-03 X107 M To convert them from M to ppm first what se ppm, we known bbm → ports per million bos bpm = 10-6

to do this we known the molar mes of Kt Molar mess=kt 39.09 g/mol i moles | 2 of K+ 1.806x10-6 mof x 39.099|reot 70 59 x 10-6 g/L ng of kt, so he want noles /L of kt 70.59x16 g 12 x 1000mylab

moles 12 of kt 70.59 X 10–3 mille 70.59x100 ngle pole | 4 0 4t because ppm and 10-6 ingle = 10-3 10-6 103 ppm = mg/l 3 kt 70.59 X100ppm kt 0.07059 ppm SPmilarly (so Molay mess 32+ 164) 96 glonal [504?] 9.03 × 157 not ll x ab gi noe 86688x1077 old to consent it to my Igle x 1000mg 108 mg/h 8 66,88 x10-7 866-88 x 10-4 or 0.08 66 ppm (soy This whole process is unit conversion. Hope you under Stant 22