Suppose a tank contains 631 m3 of neon (Ne) at an absolute pressure of 1.01 105 Pa. The temperature is changed from 293.2 to 293.6 K. What is the increase in the internal energy of the neon?
the increase in the internal energy of the neon = 3/2 * nR * (T2 - T1)
= 3/2 * (26144.28) * 8.314 * (293.6 - 293.2)
= 130418.126 J
Suppose a tank contains 631 m3 of neon (Ne) at an absolute pressure of 1.01 105...
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