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Assume a random variable Z has a standard normal distribution (mean 0 and standard deviation 1). Use all decimal places from

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1.55 and 1.86 @ The probability that a les between = P(-1.55 <2c 1.86) = P(Z <1086) - P(Z <4.55) = 0.9686 - 0.0606 = 0.9080

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