Homework Answers
Here we apply concept of center of mass of system of particles.
![→ Hem = (40) (-5) + (350) ED) + (346122(40)] (140 +350 +306.12) - X = 2.02 cm I or Xcm = 2.com New center of 2 cm away - cent](http://img.homeworklib.com/questions/0ec56b80-9ad5-11eb-b473-3323fcb5228d.png?x-oss-process=image/resize,w_560)
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2. In lacrosse, an attacker's stick is 101.6 cm long. The stick is 350 g and...
A 60 newton hand and forearm are held at 90 degrees, the center of gravity of...
A 60 newton hand and forearm are held at 90 degrees, the center of gravity of the forearm is 20 cm from the elbow joint center. Assume the tendon of the biceps muscle attaches at a 90 degree angle to the forearm at a point 4 cm from the elbow joint center. How much force must the biceps muscle produce to maintain this position?
11. A 40 newton hand and forearm are held at 90 degrees, the center of gravity...
11. A 40 newton hand and forearm are held at 90 degrees, the center of gravity of the forearm is 15 cm from the elbow joint center. Assume the tendon of the biceps muscle attaches at a 90 degree angle to the forearm at a point 4 cm form the elbow joint center. How much force must the biceps muscle produce to maintain this position? Hint: use net torque to solve. (5 points) Tm = F. Xd Center of rotation
9. A meter stick is supported by a knife edge at the 50-cm mark. Doug hangs...
9. A meter stick is supported by a knife edge at the 50-cm mark. Doug hangs masses of 0.40 and 0.60 kg from the 20-cm and 80-cm marks, respectively. Where should Doug hang a third mass of 0.30 kg to balance the stick? (state the position on the stick) Draw the Free-Body Diagram. 10. A uniform bridge span weighs 50.0 × 10 N and is 40.0 m long. An automobile weighing 15.0 × 10, N is parked with its center...
You hold 1.80 N softball in your hand as shown in the figure. Consider your forearm and hand to b...
please answer question 2
You hold 1.80 N softball in your hand as shown in the figure. Consider your forearm and hand to be a uniform rod with a mass of 1.25 kg and the distance between the elbow on t and the ball in your hand is 2L # 24.0 cm. Your biceps exerts an upward force of 14.0 N on the forearm and is attached at a distance of d :* 2.20 cm from the elbow. Baceps Mg...
Find the elbow joint reaction force (magnitude and direction) and the elbow flexor muscle force for...
Find the elbow joint reaction force (magnitude and direction) and the elbow flexor muscle force for the instant described below. Assume the forearm, hand, and ball to be a single rigid body. This rigid body has a mass of 3 kg; it has a mass moment of inertia about its center of mass of 0.018 kg*m2 ; its center of mass is 19 cm from the center of the elbow joint. The rigid body has an angular acceleration (α) of...
How much force (in N) must the biceps muscle exert when a 25.0 kg mass is...
How much force (in N) must the biceps muscle exert when a 25.0 kg mass is held in the hand in a stationary position when the arm is 17.4° below the horizontal? Assume the mass of the forearm is 2.46 kg. Distances relative to the elbow joint are reb = 5.12 cm; recg = 16.5 cm; ren = 37.5 cm where the distances are: eb = elbow—biceps; ecg = elbow—forearm center of gravity; eh = elbow-hand. A marble column 0.890...
Consider the case of the bicepts muscle acting on a forearm holding a 43 N weight....
Consider the case of the bicepts muscle acting on a forearm
holding a 43 N weight. The forearm is 30° below the horizontal and
the bicepts muscle inserts at an angle of 45° with the forearm. The
muscle insertion is at 5 cm from the elbow joint. The forearm has a
weight of 21 N and has its center of gravity 15 cm from the elbow.
The 43 N weight is held in the hand 30 cm from the joint...
A man holds a 182-N ball in his hand, with the forearm horizontal (see the figure)....
A man holds a 182-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M, which is applied perpendicular to the forearm. The forearm weighs 19.3 N and has a center of gravity as indicated. Find (a) the magnitude of and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to...
Please help thank you! Three masses are attached to a uniform meter stick, as shown in...
Please help thank you!
Three masses are attached to a uniform meter stick, as shown in the figure. The mass of the meter stick is 0.5 kg and the masses to the left of the fulcrum are m = 4.4 kg and m2 = 4.8 kg. Find the mass my need to be attached to the right end of the stick to balance the system - 30 cm 40 cm - 30 cm A wheel rotates without friction about a...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
11. A 40 newton hand and forearm are held at 90 degrees, the center of gravity of the forearm is 15 cm from the elbow joint center. Assume the tendon of the biceps muscle attaches at a 90 degree angle to the forearm at a point 4 cm form the elbow joint center. How much force must the biceps muscle produce to maintain this position? Hint: use net torque to solve. (5 points) Tm = F. Xd Center of rotation
9. A meter stick is supported by a knife edge at the 50-cm mark. Doug hangs masses of 0.40 and 0.60 kg from the 20-cm and 80-cm marks, respectively. Where should Doug hang a third mass of 0.30 kg to balance the stick? (state the position on the stick) Draw the Free-Body Diagram. 10. A uniform bridge span weighs 50.0 × 10 N and is 40.0 m long. An automobile weighing 15.0 × 10, N is parked with its center...
please answer question 2
You hold 1.80 N softball in your hand as shown in the figure. Consider your forearm and hand to be a uniform rod with a mass of 1.25 kg and the distance between the elbow on t and the ball in your hand is 2L # 24.0 cm. Your biceps exerts an upward force of 14.0 N on the forearm and is attached at a distance of d :* 2.20 cm from the elbow. Baceps Mg...
How much force (in N) must the biceps muscle exert when a 25.0 kg mass is held in the hand in a stationary position when the arm is 17.4° below the horizontal? Assume the mass of the forearm is 2.46 kg. Distances relative to the elbow joint are reb = 5.12 cm; recg = 16.5 cm; ren = 37.5 cm where the distances are: eb = elbow—biceps; ecg = elbow—forearm center of gravity; eh = elbow-hand. A marble column 0.890...
Consider the case of the bicepts muscle acting on a forearm
holding a 43 N weight. The forearm is 30° below the horizontal and
the bicepts muscle inserts at an angle of 45° with the forearm. The
muscle insertion is at 5 cm from the elbow joint. The forearm has a
weight of 21 N and has its center of gravity 15 cm from the elbow.
The 43 N weight is held in the hand 30 cm from the joint...
A man holds a 182-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M, which is applied perpendicular to the forearm. The forearm weighs 19.3 N and has a center of gravity as indicated. Find (a) the magnitude of and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to...
Please help thank you!
Three masses are attached to a uniform meter stick, as shown in the figure. The mass of the meter stick is 0.5 kg and the masses to the left of the fulcrum are m = 4.4 kg and m2 = 4.8 kg. Find the mass my need to be attached to the right end of the stick to balance the system - 30 cm 40 cm - 30 cm A wheel rotates without friction about a...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
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