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A battleship that is 5.85 times 10^7 kg and origin

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Answer #1

(a) conserve momentum: initial p = final p
0 = 1100kg * 595m/s + 5.85e7kg * v
v = -0.011188 m/s = -11.2 mm/s

(b) Ek = ½(1100kg * (595m/s)² + 5.85e7kg*(0.011188m/s)²) = 194.7 MJ

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