Question

A cord connects two bodies of weights 400 N and 800 N. The two bodies are
placed on an inclined plane and cord is parallel to inclined plane. The coefficient
of friction for the weight of 400 N is 0.15 and that for 800 N is 0.4. Determine the
inclination of the plane to the horizontal and the tension in the cord when the
motion is about to take place, down the inclined plane. The body weighing 400 N
is below the body weighing 800 N.

Answer 1

Wisine Witos it wo sing . 800 N . w.coso UDON N, W, 10s0 2 400 Cose Ny z W21058 = 800 COS O Block 1 moves down when . We sino > Tit Ffi T + MN = T+0,15x400 100 400 sino ? T + 0.15 x 400 LOS O & Block 2 moves down when T + H₂ sino > Ff2 = M N 2 = 0.4 x 800 cosa T + 800 kind > 0.4x 800 coso. => 29 0 eq Is (400) Laing - 0.15 COSB) - T, > (800) Lorincoso - Ane) - Tv T => TE 906 (rino -0.15 (018) - soo cau losa - ning) linn -0.15 10s0 z 0.3 CM10 - 2 sing 3 sino a 0.95 Lose - tang = 2.12-5712580 Ti hoo (Kim 11.571259 -0.45 cos 17-521258) = 63.556 N) - Tz