Question

A population has a mean of 300 and a standard deviation of 80. Suppose a sample size 100 is selected and is used to estimate u. Use z-table. a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) .55 b. What is the probability that the sample mean will be within +/- 11 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) .8664 The Food Marketing Institute shows that 18% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.18 and a sample of 600 households will be selected from the population. Use z-table. a. Calculate o(P), the standard error of the proportion of households spending more than $100 per week on groceries (to 4 decimals). .0159 ♡ b. What is the probability that the sample proportion will be within +/- 0.03 of the population proportion (to 4 decimals)? 1.886 c. What is the probability that the sample proportion will be within +/- 0.03 of the population proportion for a sample of 1,300 households (to 4 decimals)? .9500

Answer 1