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The equilibrium constant for the following reaction is 1.71×10-2 at 847 °C. 2 SO3(g)2 SO2(g) +...

The equilibrium constant for the following reaction is 1.71×10-2 at 847 °C.

  • 2 SO3(g)2 SO2(g) + O2(g) K = 1.71×10-2 at 847 °C

Calculate the equilibrium constant for the following reactions at 847 °C.


(a)   2 SO2(g) + O2(g)2 SO3(g) K =


(b)   SO3(g) SO2(g) + 1/2 O2(g) K =

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Answer #1

2SO3 198 2 Soz + O₂ (9) (3) K = 1.71 10 2 Equilibrium le constont at 847 C mass action law K is given by [s0,3 [02] (503) 171sos be (6) SO₂(g) + 2 O2 (9) 099 k Let equilibrium constant [s0,3 [0] [sorg] con be written It 어 k [ Length [soa] ² [oz 21

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