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A wire of length 0.75 m is conducting a current of 1 = 6.3 A in the x-direction through a B = 5.0-T uniform magnetic field th
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100 I Given l=0.75m I = 6.3 B = 5T Magnetic force on wire P = (2x) > È ILB. sine Here 0 = 180° = ² = - ILB Sin 180 Hence the7 => B = 6.3x0.75 -> B² 1,481 Now † - i (y direction ľ - i (a direction) F = I lx B êx (-²) J = Hence the magnetic fierd dire

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