Question

In java use input validation to have user enter hourly rate between 10 and 50.50 And output to screen if errors must be in java!!

Answer 1

import java.util.Scanner;

//TestCode.java
public class TestCode {
  public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    double n;
    while (true) {
      System.out.print("Enter hourly rate: ");
      n = scanner.nextDouble();
      if (n < 10 || n > 50.50) {
        System.out.println("Error: Invalid input");
      }
      else{
        break;
      }
    }
    System.out.println("Hourly rate: "+ n);
  }
}

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