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A cell phone company offers two plans to its subscribers. At the time new subscribers sign up, they are asked to provide some

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Answer #1

We frame the Null Hypothesis

он: The Mean Income of those selecting Plan B is larger.

To Test the он we use the t - Statistic

Z T-y 2 + ni

Z= 58200 - 58400 81000000 43 + 75690000 42

Z= |-2001 1883720.930 + 1802142.857

Z= 1-200 3685863.787

\Rightarrow Z = \frac{\left | -200 \right |}{1919.8604}

Z -0.1042

Zcal 0.1042

:. Zcall 0.104

Given \alpha = 0.02 = 2%

\Rightarrow Z_{cri} = Z_{\alpha } = Z_{0.02} = 2.33

Since  Zcal < Zeri; So we Accept он at 2 % Level of Significant

Therefore we conclude that "The Mean Income of those selecting Plan B is larger".

p-value:

p value is 0.4585

NOTE: To See the Critical Values of Z; we use the Standard Normal area tabulated values which i posted below.

How to see?

If alpha = 2% the confidence interval = 98% (Or) Vice-Versa

Divide the value 98 with 100. you will get 0.98 and after that divide the value 0.98 with 2; you will get 0.49. Now Search this 0.49 in side the table ( repeating again see inside the table). You will find this at the intersection of (2.3, 0,03) which is Zcri value i.e 2.33

Like this you can find the Zcri for any alpha values.

Normal Distribution Table a 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.0000 0.0040 0.0080 0.0120 (0.0160 0.0199

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