Question

1) Determine the force in member BE and state if the member is in tension or compression.

2) Determine the force in member EF and state if the member is in tension or compression.

3) Determine the force in member CB and state if the member is in tension or compression.

Consider the truss shown in (Figure 1). Suppose that F1 = 6 kN and F2 = 10 kN. Figure 1 of 1 4 m E 4 m B F F 4 m 4 m

Answer 1

Dear student,

Inorder to calculate the forces in the members BE, EF, CB we can apply method of section. Such that we sectioning a the three above members.

Initially tension was assumed, after if result comes negative then we consider it as compression.

Numerical solved below,

Soin 07-07-2020 Given Pizbko 4m F = GAN. X yo F2=1 4n F F2=10KN 4m. G VAX qk um en VG. NAY determined by can be we * Force Pn members method of seltion BE, EF CB. * Before the can calculate Reaction force. Efy = 6 KN =) Vay = 6754 VAY = -48KN. Erol VAX + lot 6+10=o. VAX = -26 KN. VAY + VG IMA. (10x4) + (0x8) + (6x 12) +6x4) (VGxy VG2 54 KN.

- By Method of section fee cloves Fec FEF F B FBE cosur, F2=lokN. Vax=26 kN. A 1 VG G Vgt = 54KN. VAY = 48 KN EF=0 - 48 +54 + FBE sio 45 + FBC & FEF=0 6 جا EFxzo! 10-26 +FBE60545=0. FBE = 22.62 kN. I tension) EMB=0 sy - o. (26x4) (FEFX 4) -(84x4) FEF=-28KN 60 Fes= 28 KN. (compression)

From en Q. -48 +54 +22.62 Sin 45+ Foc - 28.50. fexor Fac= 6.019 KN Tension Resultti FBE = 22.62 KN (Tension) FEF= 28 KN ( Compression) F CB = 6.019 KN (Tension)

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