Question

A magnetic actuator is shown below, where the number of turns is N and μο-4m* 10-7 H/m. 515, the cross section area of magnetic core is Ac-430 mm2, te airgap width is x-7 mm, the current 1-1.4 A, Magnetic actuator

Answer 1

Energy stored by actuator = 1/2 LI^2 we know, LI = N phi = N times Mmf/reluctance LI = N times NI/R or L = N^2/R = N62/l mu_0 A = 515^2 times 4 pi times 10^-7 times 430 times 106-6/14 times 10^-3 = 0.0102 (d) Energy stored = 1/2 times 0.0102 times 1.4^2 = 10 mJ (e) Force times displacement = energy therefore force = 10 mJ/7 m = 1428.57 mN