Question

A 1600 kg weather rocket accelerates upward at 10 m/s. It explodes 2.2 s after iftoft and breaks into two fragments, one twice as massive as the other. Photos reveal that the lighter fragment traveled straight up and reached a maximum height of 520 m. Part A What was the speed of the heavier fragment just after the explosion? Express your answer using two significant figures. 190 AED Submit Previous Answers Request Answer

Answer 1

we know that . v=utat uz final speed u= initial speed to a=acceleration somis? time t= 2:25 sos v - (102-2) wis 7 = 22 m/s The momentan tust before the explosion is , Pia mo. e of q is speed mass 2n , of then the portion final morentun - Pq 2 m + 272

by Conservation of monentur, Pi=pG 3 Vevo na tayo giver, that the lighter reached to a manimum mass reight ho 520m. at the instant of enplosion the height was n'a Lat's {10x12:23 m »ña 24.2m so entra height that the lighter mass has to cover with Breed u e unan gravity is sanana (520-24.2) ir final speed Now, we know that is a'zo tun v² = v²_295

- 0² v,2-2gs . > via Tags wsing equation -&), ie 9 PT + 3) V2 = 30 - va que va ser av. R222) - 110482 520-263} - 2) V -16.289468ws / sign Velocity indicates vertically that it has downwards 59, speed (magnitude of velocity) is llomis (appron in two significant figures)