Question

PART B - NITROGEN AND RELATED COMPOUDS Formula Lewis Structure Formula Lewis Structure NH, NO, N.H PO NHOH PBr 1. How many bonds does nitrogen typically form? Does this make sense based on the number of valence electrons in a nitrogen atom? Explain your answer. 2. Does phosphorus typically form the same number of bonds as nitrogen? Use the periodic table to explain why your answer makes sense. 3. Circle the structures below that represent a typical bonding pattern for nitrogen. N N N N N N N=

Answer 1

Answer:

First I will briefly discuss steps to draw Lewis Structure:

Step 1: Calculate number of valance electrons of the molecule. eg H2O would have 8 valance electrons ( 6 of oxygen and 1-1 each from 2 Hydrogen atoms)

Step 2: Place the elements in drawing and draw electrons between atom which form chemical bonds.

Step 3 : Draw the rest of electrons and the structure is complete.

Solutions of the questions are attached

I Part B - Nitrogen related compounds: Formula Lewis structure NH3 E • • • • H. N₂ H2 HooN : W..H_= N- - 1 , 0 |H • • • • O H = H -- Ố–H NO 1:03. N:rö \NZO Zelectrono one additional electron This ed ditimol electron responsible + for negative charge. óo - ; 0 P -O', POS 1:.P..0:1 :6: Scanned with CamScanne

p Br : Bye . p .. Br: ² :Br-P - Bri • BY -: Bri Scanned with CamScanner

Nitrogen has 7 electrons, so Electronic configuration of Nitrogen is! Nitrogen : 11 IV alalla - IS- here, we know that nitrogen does not have d orbital, so clearly it has only 3 Beestenbeo unbaired electrone Only ambalred electrons form a covalent bond so nitrogen typically forms 3 bonda But in some cases it forms one additional coordinate covalent bond with the help of lone pairs, so it con form 3+1 = 4 bonds fes Sput cleally nitrogen forms 3 bondh. CamScanner

I Phosphorus Electronic has is electrons, configuration is! so IP = (Ne s² 363, and it has vocant d orbital. 111 17 10 II 35 3k - 3d in ground state phosphorus has 3 Unpaired electron but in excited state it has 5 un paired electrons's exclted state. 3d the energy nauired for excitation is easily adeat available at room tempratune. Soed phosphras typically forms 5 bondse CamScanner

(3) NE – NEW N=- z According to Lewis structure rule, only these two can be typical bonding •d hangovih of nitrogen. 'CamScanner