Question

Method of Joints Refer to the diagram - The joints are capital-lettered in green. For each joint, "cubicle" the joint detail, its force loop, and the joint's EX and Y equilibrium equations. Label, arrow-counterarrow, and color blue for compression, red for tension. Separate each joint solution by a solid line. 12004 12004 1200 900# H 900- Rung 1 Rmx 811 ty.ca Rmi =0 1.: RG4 = 2700 # oated Rmy= 2700 #

Answer 1

1200 12.00 D C 1200 F 900 H A RG M RM Givena BM: 2700 # B. * 2ệm 4 36-86 6 At pt M force in Hember Mk :o due to I-sector. Foto 1 BO EAN = R 2 700 # RA At pt. A & fx=0 Es sind = FAM - 900 FAB: 3000 # LO 900# FAX At FAM FAR Es cose 3 FAK Eur : 2400 # (1) 7 10

At pt. k EAR = Fkg Cos o FRT 3000 # (1) to FRI FA FKB · Ekg Sino FSB 1800 # (2) E At pt. B 1200 8 Efy=0 Fac Sind + 1200 = FAB Sia o + Fok EBE 4000 # (c) KEBC FBI FAE 1 вк Efx=0 EBJ + Foc cos 0 = F87 : - 800 # FAB Caso Similiarly At pt. G, F & H. FFG = 7000 # (c) FHG = 0 FHF = FHI = 3400 # (1) THE = o (Due to I-section) 2000 (c) At pt. D EpE = 1200# (C) (Due to T-section

At pl.c 1200# KFCE Efx=0 FEE FBc Caso Free 3400# (C) FBC FI Efy:o FBc Sino = Fi 1200 + FCI (1) 1200 # At pt. E FCE IFE 6 & Fro Ece = FEL Cos o tref Cos FEI = 1000 # (1) Fast FEE