Question

A chemist titrates 100.0mL of a 0.6816M propionic acid HC2H5CO2  solution with 0.7302M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of propionic acid is 4.89.Round your answer to 2 decimal places.Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.

Answer 1

9 point Al equivalence moes of aud = moles of base 0.6816 x 100 = 0.7302 x v T = 93.34 me since at eg point all the conc. of acid the conc. base. and is neatrilise by forms salt. . This is hydrolysis the problem of salt PH = 7 + pka & log [scott] [ salt] = [C2 Hg CO₂ Na] = moles Total volume 0.6816 x 100 100+ 93.341 = 0.352 M VH = 7 + 4.89 + log (0.352) [PH = g. 22] Ans.