Question

Questloh 21 14 points) An agricultural company wishes to see if the there is any difference in yield for each of 1 = 4 brands of corn seeds. To do this they divided a large field into 24 equally-sized plots and for each plot randomly chose a seed to use such that each brand of seed was used in exactly J = 6 plots. An analysis of the resulting data gave a Total Sum of Squares of 23625 and an Error Sum of Squares of 13212. What is the the value of the test statistic to test the null hypothesis of no difference in the mean yield from the different brands of seed? OA) 0.7881 OB) 1.7881 O C) 3.9407 OD) 11.9210 OE) 5.2543 Question 22 (4 points) Based on the data given in Question 21, an unbiased estimate of the variance in yield amounts for any single seed type is

Answer 1

Question 21.

CALCULATION:

brands (t) = 4, n = 24

DF_Brands = t-1 = 4-1 = 3

DF_Error = n-t = 24-4 = 20

DF_Total = DF_Brands + DF_Error = 20+3 = 23

SS_Brand = SS_Total - SS_Error

SS_Brand = 23623 - 13212

SS_Brand = 10413

MSS_Brand = SS_Brand / DF_Brand = 10413 / 3 = 3471

MSS_Error = SS_Error / DF_Error = 13212 / 10 = 660.6

Test statistic (F) = MSS_Brand / MSS_Error = 3471 / 660.6 = 5.2543

ANSWER: E. 5.2543

ANOVA TABLE:

SS 5.2543 Source df Brands error Total 3 20 23 MSSF 10413 3471 13212 660.6 23625

ANSWER: E. 5.2543