A camper is about to drink his morning coffee. He pours 400 grams of coffee, initially...
A camper is about to drink his morning coffee. He pours 400 grams of coffee, initially at 75.0°C, into a 250-g aluminum cup, initially at 16.0°C. What is the equilibrium temperature of the coffee-cup system, assuming no heat is lost to the surroundings? The specific heat of aluminum is 900 J/(kg·K). Assume that the specific heat of coffee is the same as the specific heat of water.
Homework Answers
Let final temprature beT.
Heat lost by coffee= mCdT
=0.400*4180*(75.0-T)
Heat gained by cup= 0.250*900*(T-16)
For no heat lost.
Heat lost by coffee= Heat gained by cup
0.400*4180(75-T)=0.250*900(T-16)
T=68 ?
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