Question

Fused quartz possesses an exceptionally low coefficient of linear expansion, 5.50 × 10-7 (C°)–1. Imagine you had a bar of fused quartz of length 3.45 m at 20.0°C. By how much, in millimeters, would the bar expand if you heated it to 237°C?

Fused quartz possesses an exceptionally low coefficient of linear expansion, 5.50 x 10% (Co)-Imagine you had a bar of fused quartz flength 3.45 m at 20.0℃. By how much, in millimeters, would the bar expand if you heated it to 237°C? Number

Answer 1

(sto) ( t6") = (L-3.us ) (3.ys 237-20) (sSo)(面7)(148.65) L-3.ys =

Answer 2

The length change Δ?$\mathrm{\Delta }L$ from given initial length ?0$L_0$ due to temperature change Δ?$\mathrm{\Delta }T$ is

$$\mathrm{\Delta }L=\alpha L_0\mathrm{\Delta }T$$

$$\mathrm{\Delta }T=T-T_0$$

Substitute this in the expression for Δ?$\mathrm{\Delta }L$ to obtain the requested change of length in terms of given quantities.

$$\mathrm{\Delta }L=\alpha L_0(T-T_0)$$

For the numerical answer, insert the data and convert the result to millimeters, as requested.

Δ?=[5.50×10−7(C°)−1](2.89 m)(201°C−20.0°C)=0.000288 m=0.288 mm