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A mass of 0.160kg is attached to a spring of spring constant 41.0 N/m if the...

A mass of 0.160kg is attached to a spring of spring constant 41.0 N/m if the mass executes simple harmonic motion, what will be the period (T) of its motion ?

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Answer #1

We know

angular frequency, w = sqrt(k/m) (here k is spring constant and m is mass)


and time periode, T = 2*pi/w

= 2*pi*sqrt(m/k)

= 2*pi*sqrt(0.16/41)

= 0.393 s

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