Question

that can calculate several statistical measures of data. Write a program collects N integers from the user (N is a positive integer entered by the user). Then, the program prompts the user for an option: 1- to find the minimum, 2- to find the maximum, 3- to find the mean, 4-to find the standard deviation. In addition to the main method, your program must contain four methods with the following headers: The program public static int min(intlI A) public int max(intll A) public double mean(intll A) public double std(intlI A, double mean) Use the following formulas to calculate the mean and the standard deviation. mean- ri i- 1 standard deviation N-mean)2 The following is a sample run. The bold letters are printed by the program. The non-bold letters are entered by the user ase enter N: ase enter the 5 integers: Please enter an option: standard deviation is 3.9293765408777

Answer 1

Below is the C++ code I hope that i have provided sufficient comments for your better understanding

#include<bits/stdc++.h>
using namespace std;

//declaration
int minimum(int* A);
int maximum(int* A);
double mean(int* A);
double deviation(int* A,double mean);

//global variable
int n;

int main()
{
int choice,p;
double q;

//Take user's input
cout<<"Please enter N : ";
cin>>n;
int a[n];

cout<<"Enter "<<n<<" integers : "<<endl;
for(int i=0;i<n;i++)
cin>>a[i];

cout<<"Enter an option\n";
cout<<"1. Find minimumimum"<<endl;
cout<<"2. Find maximumimum"<<endl;
cout<<"3. Find mean"<<endl;
cout<<"4. Find standard deviation"<<endl;
cin>>choice;

switch(choice)
{
case 1:
p=minimum(a);
cout<<"Minimum value is "<<p;
break;
case 2:
p=maximum(a);
cout<<"Maximum value is "<<p;
break;
case 3:
q=mean(a);
cout<<"Mean value is "<<q;
break;
case 4:
q=deviation(a,mean(a));
cout<<"Standard deviation value is "<<q;
break;
}
return 0;
}
int minimum(int* a)
{
//initialize result as 1st value of array
int res=a[0];
for(int i=1;i<n;i++)
{
//update result if necessary
if(a[i]<res)
res=a[i];
}
return res;
}

int maximum(int* a)
{
//initialize result as 1st value of array
int res=a[0];
for(int i=1;i<n;i++)
{
//update result if necessary
if(a[i]>res)
res=a[i];
}
return res;
}
double mean(int* a)
{
double sum=0.0,res;

//calculate sum of all values
for(int i=0; i<n; ++i)
{
sum += a[i];
}
//calculate average
res = sum/n;
return res;
}
double deviation(int* A,double mean)
{
double standardDeviation = 0.0;

//calculate standard deviation
for(int i=0; i<n; ++i)
standardDeviation += pow(A[i] - mean, 2);
return sqrt(standardDeviation/n);
}

Below is the screenshot of output

Hope i have answered your question satisfactorily.Leave doubts in comment section if any.