Question

The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at 0.2 = 18.1 m/s when the eagle swoops down, grabs the pigeon, and flies off. At the instant right before the attack, the eagle is flying toward the pigeon at an angle 0 = 62.7° below the horizontal and a speed of 0.1 = 35.9 m/s. What is the speed of the eagle immediately after it catches its prey? speed: What is the magnitude of the angle, measured from horizontal, at which the eagle is flying immediately after the strike? magnitude of angle:

Answer 1

Conservation of momentum in north-South disinction mp up + me ve caso mp + me) (Ve) (26 mp L 18.1] + me [35.9] cos [-62.7] (mp + me) disrechon Conservation of momentum in East - west meve sino = (mpt me) ve sind me (35.9) Sin (-62.7) = (mp+ me) ve sino from (1) 6 (2) Tand - me (35.9) sin (-62.17) (2) mp (18+1) +me 135.9) cos (-6207) = 2m, (35-9) sin(-62.2) 18.1 +2135-9) Cos(-627) = 2(3509) sin(-62.2) 18.1+ 2(3509) cos(-62.7) - 63.80 - - 63.80 / 18.1 +32.9310 51.031. = -1.250220 - Tan (1. 250220) - - 51.345 degrees me (35.9) sin(-62.7) = (mpt me) us sind ve - 2mp (35.9) sin (-62.7) -63.8028 -2.34276 (mp+amp) sin(-51.345) ve = 27.2339 m/sec, magnitude of angle = 51.345 degreg. M /