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EXERCISES 5.4 Integration Formulas and the Net Change EXERCISES 5.4 Integration Formulas and the Net Change Theorem Score: 12.17/14 12/14 answered Question 14 A 25-year old woman burns 300 - 80t cal/hr while walking on her treadmill. Her caloric intake from drinking Gatorade is 95t calories during the tth hour. What is her net decrease in calories after walking for 3 hours? calories burned Submit Question

i also need the right answer for my last question in my second post

Answer 1

1. A zsyears old woman burns 300-8ot call hr. In three hours calories burns = {(300-80t) at = 300t - 80. th] =300*3- 80x9 =900-360 = 540 calories She burns calories = 540 In 3rd hour she drink Gatorade having calories ist She gain calories = 95x3 = 285 calories Met decrease in calories = 540-285 = 255 Net decrease in calories = [25s calories burned. 2. For the last part we will find distance travelled in 3 minute. distance is always positive Velocity function V (t) = -8 Const) -8 which is periodic function, then we find when velocity changes. VCU)=0 = -8 const) -6=0 - Copct) = - = -0.75 t = cos(-0.75) = 2.419. Sowe find distance travelled in oto 2.419 seconds and 2.419 to 3 seconds. dátanco = 112-8 Cooch) - Jat | + 1 SE-scoces-] *t = (1-8sint -6+ || 2.43 +4 -2cant -+ - 1-8 sin (2_419) - 662.419) -o|| + 1f-8a(3) -6(3)}-{-891(2415) = 1-19.8051| + -19.129+19.80511-6624419)3|| = 19.805+0.676=20.481 Distance = (20.481 meter 2.419 2-419