Question

10.00 points Air 129 MPa and 334 Kows upward through a 0.084-m-diameter inclined duct at a rate of 65 USThe duct diameter is then reduced to 0.064 m through a reducer. The pressure change across the reduceris measured by a water manometer. Determine the differential height between the fluid levels of the two arms of the manometer in centimeters The oferential height between the fuld levels of the two arms Hints esc 80 888

Answer 1

coiven, P. T 129 kPa 334K d =0.084 m a = 654 da = 0.064m. A = 77 22 7 1 1 C 0.08452 = 5.541768108 m2 A2 = 7 d ² = 1 (0-064)² = 3.21699 x 10 m² Velocity, via a = 65x ( 1 ) = 116729 m/s 5.54 Vzd - Box Content z = 20.2052 ml, 3.2 1699 xlos Density, P = Sain RT 129 = Sair (0.287 55 Ang ke ) X 334 Sair = 1345 kg/m3 Bernoulix Equation, -tZ; + Zz. Sairxg 29 Sairlg 29 z = 7₂ = 0 - [Not given

Pi-Py = fair ag [ en ] = 1:345X9:21 [(20-20) – (1-720) 2x9-81 = 1-34589.81 [ 408.24 - 13 456 2x9-8) Pi-P2 = 183.93pa P-P2 = Swxgxh. 183.93 = 1000 X 9.818 h Th=0.8200359 m