Two charges are located on the x-axis at 1.30 m both with a charge of +160...

Question

Question

Two charges are located on the x-axis at 1.30 m both with a charge of +160 nC A charge on the y-axis at y = +.40 m with a cha

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Answer 1

Answer #1

V = 2kQ/ R

R = ( 0.4 ^2 +0.3^2)^1/2=0.5 m

V = 2 x 9x 10^9 × 160 x 10^-9/0.5 = 5760V

V at origin = 2kQ/r

= 2 x 9 x 10^9 × 160 x 10^-9 / 0.3 = 9600V

Change in kinetic energy = work done

= 9600 - 5760 ) × 80 x 10^-9 = 3.07 x 10^-4 J

Kinetic energy as it passed origin = 3.07 x 10^-4J

Answer 2

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