Question

better to use asa 4. If you have the same number of moles of a salt, which one would be roadway de-icer: NaCI or CaCl2? Remember, colligative properties are mole-based calculations. Show calculations to support your answer and assume both salts dissociate completely. (Assume some number of moles of each and show the calculations to the new freezing point of water to support your answer.)

Answer 1

I would prefer to use CaCl₂ than NaCl for same number of moles since both dissociate completely the number of ions are more in case of CaCl₂ than NaCl.

Depression in freezing point = Kf *m*i

where M is molality of solution and i is vontHaff factor i.e number of ions formed after dissociation.

Since i is 3 for CaCl2 and 2 for NaCl

Hence depression is more for CaCl2 than NaCl.

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