H0:
= 36
Ha:
< 36
Test statistics
t = (
-
) / ( S / sqrt(n) )
= ( 34.43 - 36) / ( 3 / sqrt(9) )
= -1.57
This is test statistics value.
Critical value at 0.05 level with 8 df = -1.860
Since test statistics t > -1.860, Do not reject H0.
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