probability a subc omponant will live beyond 1000 Hours =e-0.002*1000 =0.135335
therefore subsystem will live beyond 1000 hours =P(at least one of 5 live beyond 1000 Hours )
=1-(1-0.135335)^5
=0.517
Five identical units are arranged in a standby redundant configuration to form a subsystem. Unit failure...
Five identical units are arranged in a standby redundant configuration to form a subsystem. Unit failure is independent. If the units have exponential time-to-failure distributions with failure rate 0.002, what is the probability the subsystem will live beyond 1,000 hours? Answer to three decimal places. The answer is .947. please be detailed