Question

007 10.0 points What current is required in the windings of a long solenoid that has 732 turns uniformly distributed over a length of 0.337 m in order to produce inside the solenoid a magnetic field of magnitude 0.0001144 T? The permeablity of free space is 1.25664 × 10 -6 Tm/A. Answer in units of mA 008 10.0 points

Answer 1

Using this equation:

B = ?0 x N/L x I

B = 1.144 x 10-4 T

?0 = 1.25664 x 10-6

N/L = 732 turns/0.337 m = 2172.11 turns/meter

B = ?0 x N/L x I

I = B / ( ?0 x N/L)

I = 1.144 x 10-4 T / (1.25664 x 10-6)(2172.11 turns/meter)

= 0.0419 A

= 41.9 mA