Question

(a.2) Find the theoretical cut-off frequency (3 dB).
Fill in the table of item VI.a for the theoretical values.
Choose frequency values starting a decade below
cutoff frequency up to a decade higher on a logarithmic scale. Or
that is, if the cutoff frequency was 77 Hz, your choice would be f =
(7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 77, 80, 90, 100, 200, 300,
400, 500, 600, 700) Hz. consider in the circuit
of Fig. 1, R = 3.636 kΩ

V wide 4 Vpn Figura 1

Answer 1

* The cut off frequency is

                                                            f_cut = 1/(2*pi*R*C) = 43.77kHz

* Frequency range for calculation should be from 4.377kHz to 437.7kHz with total 20 points. Table for frequency, gain, gain(dB) and phase is shown below:

Frequency(kHz)	Gain	Gain(dB)	Phase(degree)
4.375	0.995	-0.04	-5.71
5.575	0.992	-0.07	-7.26
7.104	0.987	-0.113	-9.22
9.052	0.980	-0.182	-11.69
11.536	0.967	-0.292	-14.70
14.700	0.948	-0.464	-18.57
18.73219	0.919	-0.731	-23.18
23.869	0.878	-1.131	-28.61
30.416	0.821	-1.712	-34.81
38.759	0.749	-2.516	-41.54
49.389	0.663	-3.569	-48.46
62.935	0.571	-4.870	-55.19
80.197	0.479	-6.390	-61.39
102.19	0.393	-8.100	-66.82
130.22	0.318	-9.930	-71.43
165.94	0.255	-11.870	-75.23
211.45	0.202	-13.870	-78.31
269.45	0.160	-15.900	-80.78
343.35	0.126	-17.970	-82.74
437.52	0.099	-20.040	-84.29