a. atomic number of lithium is 3. so the total electron number is 3. the electronic configuration for Li is as follow
1S22S1 , the valence shell has only one elctron.
b. both Li atoms have following electronic configuration or atomic orbital configuration 1S22S1
but the molecular orbital configuration for Li2 is as follow

where
is bonding
molecular orbital and
is
antibonding orbital
the standard formula to calculate the number of bonds between two atom is
bond order= ( number of bonding orbital electrons - number of antibonding electrons) / 2
now, taking consideration of only valence electron
bond order = (2 - 0) / 2 = 1......[ here, considaring only
]
it can be concluded the there is only one between two lithim atom and it is the theoretical prove of existance of dilithim crystal.
c) this is the covalent bond because this bond is formed by shareing the electrons between two lithim atom.
2. standard molecular orbital configuration for He2

for, He2+ 
so, the bond order is = (2-1) /2 = 0.5 = positive value
the value of bond order is fraction but positive, this ion can be formed in nature but it will be very unstable due to not having proper bond. therefore, it is very rare.
Using the terms bonding, energy and stability, explain occurring compounds, but only 90 naturally occurring elements....