Question

10 points San Given: 2x10 Wood Joists (A = 13.875 in 2: Sx 9150 psi)KF 21.39 in 3. lx = 98.93 in 4: E - 1.200,000 psi) Fun (850 KF Fyn Note that I have calculated all of the adjusted values in the formulas above-you only have to determine the values of and Ke and use them appropriately. What is the Shear Capacity of the Wood Joist? A 2497 lb 22021 c. 283016 D. 3746 lb Moving to another question will save this response. Question 1 of 13

Answer 1

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The answer is given below.

& Giren: 2x10 Wood joists 4.625" 1 1/" A = 13.875in2 Sx = 21,3930? Ix=98.93 in4 E = 1,200,000psi Fbn = $(850psi) Fun= $(150 psi) KF VD As per the American Klood Council, d6=0.85; to 0.75; KF= 2.88 » Fbn=722.5psi Fun= 324 psi We know that fun- SFX & max Iuxt Sf. Smax Shear force First Moment of Area above respect to neutral axis. centroid with 1x – Moment of Inertia of cls. to Thickness @ centroid. Smax = 15X4.625x 2.3125= 4107 2 16.043 in? 256 sin t= 1.5in.

324 = SEX 16,043 98.93x 1.5 → SF = 2996.95 lb