consider a car moving in the positive direction with an initial velocity of 39m/s slows down at a constant rate of -0.5m/s square. the distance traveled by car is ____ m
Using 3rd equation of motion,
V^2 = u^2 + 2as
0 = 39^2 - 2 x (-0.5) x s
Distance, s = 1521 m
Comment in case any doubt please rate my answer.....
consider a car moving in the positive direction with an initial velocity of 39m/s slows down...
Consider a car moving in the positive direction with an initial velocity of 37 m/s slows down at a constant rate of -1.5 m/s2. What distance does the car cover in 10 seconds in meters?
Consider a runner moving in the positive direction with an initial velocity of 5.8 m/s slows down at a constant rate of -0.7 m/s2 over a period of 2 seconds. What is her velocity at the end of this time? ______ m/s
A runner moving with an initial velocity of 15.4 m/s slows down at a constant rate of -2.9 m/s2 over a period of 2 seconds. (a) What is her velocity at the end of this time? (b) What distance does she travel during this process?
A driver in a moving car applies the brakes. The car slows to a final speed of 1.30 m/s over a distance of 40.0 m and a time interval of 8.20 s. The acceleration while braking is approximately constant. (a) What is the car's original speed before braking? What is its acceleration during this time? (The car's initial velocity is in the positive direction. Indicate the direction with the sign of your answer.)
A car traveling at 20 m / s slows down at a rate of 0.50m / s2. Calculate: a) The distance the car traveled when it stopped. b) The time it takes to stop. c) The distance traveled by the car in the first three seconds after it begins to decelerate.
a person runs with an initial velocity of 5.0m/s. then he slows down at a rate of -1.2 m/a square over a period of 3 seconds
Here is a simple problem involving a single step. A particle
moving in the positive direction of an x axis slows from 50.0 m/s
to 20.0 m/s at the rate of 4.00 m/s2. How much time and how much
distance are required?
Here is a simple problem involving a single step. A particle moving in the positive direction of anr axis slows from 50.0 m/s to 20.0 m/s at the rate of 4.00 m/s. How much time and how much...
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by a = 0.50t, in m/s2 for t in seconds. At the end of 2.0 s it has traveled: A) 0 B) 12 m C) 14 m D) 34 m E) 33 m. The answer is E. I got D. Why is the answer E?
1. A sports car moving at a constant velocity travels 120 m in 5.0 s. If it then brakes and comes to a stop in 4.0 s, what is the magnitude of its acceleration (assumed constant) in m/s^2 and in g's (g=9.80 m/s^2). 2. A car slows down from 28 m/s to rest in a distance of 88 m. What was its acceleration, assumed constant?
A car is initially moving at 9.9 m/s in the positive x direction and accelerates at a constant acceleration of 3.4 m/s2 in the positive x direction for 6 seconds. It then immediately has an acceleration of 6.6 m/s2 in the negative x direction. After some time, its velocity is 27.6 m/s in the negative x direction. What is the average velocity for the entire trip in m/s? Indicate the negative x direction by including a negative sign but do...