Question

Two objects of masses 1 kg and 4 kg are at rest next to a compressed spring. The spring stores an energy of 2250 j. When it is released, it gives all its energy to the blocks and falls to the ground. Now, their speeds are vi and v4. Find 04. (There is no friction.) compressed awwa released 보 4

Answer 1

mulcolour.com conservation of momentum We know that Apply Here T m, u = mq va V m4 mi ga 1 v Vq =4a 1 Now, we also know that Conservation of Energy +(P.E.) Initial (kit hinalt (CE) initial final initial KiE=o] Rest Rest condition [2] [final P.E=o] According to situation initial AE = 2250 J (gireen) 0 + 3250 = (1 m, 4,2 +), Ma Vo ) + m, vz+m V2 = 4500 m, (40)² + mq Ve ² = 4500 m, x 16 x ² + may 2=4000 to 4

2 a m.6 + m4 - ५०० T [200 = 45०० 4 225 84515 mms