Question

C++ Program

What is the output of the following code fragment?(beta is of type int.)

beta = 5;

do

{

switch (beta)

{

case 1: cout <<'R'; break;

case 2: cout

case 4: cout << 'O'; break;

case 5: cout << 'L';

}

beta--;

}while (beta>1);

cout <<'X';

Answer 1

Statement inside case 2 of switch is missing in the question. Please provide the statement in a comment to get the correct answer. However, the answer below has been provided purely by assuming what the statement would have been.

CODE:

beta = 5;
do
{
    switch (beta)
    {
        case 1: cout << 'R'; break;
        case 2: cout << 'S'; break;
        case 4: cout << 'O'; break;
        case 5: cout << 'L';
    }
    beta--;
}while (beta>1);
cout << 'X';

OUTPUT:

LOSX

EXPLANATION:

Iteration 1 of do-while loop:
    Here, beta = 5 and case 5 of switch will run and 'L' will get printed on the console.
    Now, beta-- will cause beta to become beta = 4
    
Iteration 2 of do-while loop:
    Here, beta = 4 and case 4 of switch will run and 'O' will get printed on the console.
    Now, beta-- will cause beta to become beta = 3
    
Iteration 3 of do-while loop:
    Here, beta = 3 and there is no case 3 in switch. So nothing will be printed on the console this time.
    Now, beta-- will cause beta to become beta = 2
    
Iteration 4 of do-while loop:
    Here, beta = 2 and case 2 of switch will run and 'S' will get printed on the console.
    Now, beta-- will cause beta to become beta = 1
    
Now, loop condition will become false and program control will come out of the loop as beta = 1.

Finally, 'X' will be printed on the console.

LOSX is printed on the console 

FOR BETTER HELP PROVIDE THE MISSING STATEMENT AND PLEASE RATE THE ANSWER.