An error of 0.5 oC in reading the temperature drop of the metal is what percentage error?
Percentage error = [(measured value - accepted value)/accepted value]*100%.
You have a0.5 degree error for each measurement - so the % error
is (0.5/temp)*100 - these errors are additive if you have a start
and finish temp so a 4% error at start and a 2% error at finish
gives a 6% error in your tempp change estimate.
I think anyway maybe someone would confirm that for you...
The 12 times is an estimate of your precision, or reliability -
your estimate of Standard deviation of the 12 tells you how
reliable the data were, whereas the error of the thermometer
informs about accuracy of the measured change.
An error of 0.5 oC in reading the temperature drop of the metal is what percentage...
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